От: | AndrewVK | http://blogs.rsdn.org/avk | |
Дата: | 28.04.16 17:52 | ||
Оценка: | +1 |
var min1 = new[] { 1, double.NaN, 2, 3, 4, 5, 6 }.Min();
var min2 = new[] { double.NaN, 1, 2, 3, 4, 5, 6 }.Min();
var max1 = new[] { 1, double.NaN, 6, 5, 4, 3, 2, 1 }.Max();
var max2 = new[] { double.NaN, 6, 5, 4, 3, 2, 1 }.Max();