От: | kurel | ||
Дата: | 07.04.13 18:30 | ||
Оценка: |
interface Employee {
void doWork1();
void doWork2();
void doWork3();
}
class SomeClass {
private List<Employee> employees;
public void allDoWork1() {
for (Employee each : employees) {
each.doWork1();
}
}
public void allDoWork2() {
for (Employee each : employees) {
each.doWork2();
}
}
public void allDoWork3() {
for (Employee each : employees) {
each.doWork3();
}
}
}