Здравствуйте, <Аноним>, Вы писали:

А>Re: Ну так нечестно — Java (код внутри)
Все честно: сурово и сердито. Так-то это азы: надо отличать сравнение ссылок на объекты и сравнение внутренних структур объектов.

А>int []a={1};
А>int []a1={1};
А>System.out.println( a.equals(a1) ); <--- false
Массивы — это обычные объекты, потому см. java.lang.Object:

/**
 * Indicates whether some other object is "equal to" this one.
 * <p>
 * The <code>equals</code> method implements an equivalence relation
 * on non-null object references:
 * <ul>
 * <li>It is <i>reflexive</i>: for any non-null reference value
 * <code>x</code>, <code>x.equals(x)</code> should return
 * <code>true</code>.
 * <li>It is <i>symmetric</i>: for any non-null reference values
 * <code>x</code> and <code>y</code>, <code>x.equals(y)</code>
 * should return <code>true</code> if and only if
 * <code>y.equals(x)</code> returns <code>true</code>.
 * <li>It is <i>transitive</i>: for any non-null reference values
 * <code>x</code>, <code>y</code>, and <code>z</code>, if
 * <code>x.equals(y)</code> returns <code>true</code> and
 * <code>y.equals(z)</code> returns <code>true</code>, then
 * <code>x.equals(z)</code> should return <code>true</code>.
 * <li>It is <i>consistent</i>: for any non-null reference values
 * <code>x</code> and <code>y</code>, multiple invocations of
 * <tt>x.equals(y)</tt> consistently return <code>true</code>
 * or consistently return <code>false</code>, provided no
 * information used in <code>equals</code> comparisons on the
 * objects is modified.
 * <li>For any non-null reference value <code>x</code>,
 * <code>x.equals(null)</code> should return <code>false</code>.
 * </ul>
 * <p>
 * The <tt>equals</tt> method for class <code>Object</code> implements 
 * the most discriminating possible equivalence relation on objects; 
 * that is, for any non-null reference values <code>x</code> and
 * <code>y</code>, this method returns <code>true</code> if and only
 * if <code>x</code> and <code>y</code> refer to the same object
 * (<code>x == y</code> has the value <code>true</code>).
 * <p>
 * Note that it is generally necessary to override the <tt>hashCode</tt>
 * method whenever this method is overridden, so as to maintain the
 * general contract for the <tt>hashCode</tt> method, which states
 * that equal objects must have equal hash codes. 
 *
 * @param obj the reference object with which to compare.
 * @return <code>true</code> if this object is the same as the obj
 * argument; <code>false</code> otherwise.
 * @see #hashCode()
 * @see java.util.Hashtable
 */
public boolean equals(Object obj) {
    return (this == obj);
}

А>System.out.println( Arrays.equals(a,a1) ); <--- true
См. java.utils.Arrays:

/**
 * Returns <tt>true</tt> if the two specified arrays of ints are
 * <i>equal</i> to one another. Two arrays are considered equal if both
 * arrays contain the same number of elements, and all corresponding pairs
 * of elements in the two arrays are equal. In other words, two arrays
 * are equal if they contain the same elements in the same order. Also,
 * two array references are considered equal if both are <tt>null</tt>.<p>
 *
 * @param a one array to be tested for equality
 * @param a2 the other array to be tested for equality
 * @return <tt>true</tt> if the two arrays are equal
 */
public static boolean equals(int[] a, int[] a2) {
    if (a==a2)
        return true;
    if (a==null || a2==null)
        return false;
    int length = a.length;
    if (a2.length != length)
        return false;
    for (int i=0; i<length; i++)
        if (a[i] != a2[i])
            return false;
    return true;
}

А>где справедливость?
На месте.