От: | _FRED_ | @ViIvanov | |
Дата: | 20.01.11 21:29 | ||
Оценка: | 3 (1) |
N> DataContext db = new DataContext("string");
N> Table<SDocument> tblDocs = db.GetTable<SDocument>();
N> SDocument d = new SavedDocument();
N> d.FileName = FileUpload1.FileName;
N> d.Body = FileUpload1.FileBytes;
N> tblDocs.InsertOnSubmit( d);
N> db.SubmitChanges( );
N> lblDocID.Text = d.ObjectID.ToString();