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От: |
GiBBeR
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http://jenihov.by.ru |
| Дата: | 27.08.03 09:16 | ||
| Оценка: | |||
SqlCommand myCommand = new SqlCommand();
myCommand.Connection = SomeConnection;
myCommand.CommandText = "INSERT [myTable] (myRow) value ('myValue')";
myCommand.CommandTimeout = 15;
myCommand.CommandType = CommandType.Text;myCommand.ExecuteNonQuery();