Здравствуйте, pladen, Вы писали:
public void MenuClick(object sender, EventArgs e)
{
Assembly LoadAssem = null;
try
{
LoadAssem = Assembly.LoadFile(LoadSolution);
}
catch (Exception LoadAssemExept) { MessageBox.Show(LoadAssemExept.Message); }
System.Type LoadType = LoadAssem.GetType(MainClass);
object LoadObject = Activator.CreateInstance(LoadType);
(LoadObject as Form).ShowDialog();
}
так?
If the message above is in English — means I'm wasting my work time and work computer to post here. No hard feelings
