От: | Haskell.Curry | ||
Дата: | 16.10.09 12:44 | ||
Оценка: |
apply :: [(C, C, C)] -> [(S, S, S)] -> [(CS, CS, CS)]
apply [] _ = []
apply _ [] = []
apply (x:xs) ys = apply' x ys ++ apply xs ys
where
apply' x@(x1, x2, x3) ((y1, y2, y3):ys) = (CS x1 y1, CS x2 y2, CS x3 y3) : apply' x ys
apply' _ _ = []