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От: |
Анатолий Широков
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| Дата: | 03.07.03 11:47 | ||
| Оценка: | |||
SELECT tools.toolid, tools.toolname, equipment.roomid
FROM tools LEFT OUTER JOIN equipment ON tools.equipmentid = equipment.equipmentid
WHERE roomid = %roomidSELECT tools.toolid, tools.toolname, equipment.roomid
FROM tools, equipment
WHERE tools.equipmentid *= equipment.equipmentid
AND roomid = %roomid